np argmax second
In [1]: import numpy as np In [2]: arr = np.array([1, 3, 2, 4, 5]) In [3]: ..... 1, 5, 5, 2, 3, 2, 4, 1, 0]) >>> B = np.zeros(3, int) >>> for i in xrange(3): ... idx = np.argmax(A) . , Use the command np.argsort(a, axis=-1, kind='quicksort', order=None) , but with appropriate choice of arguments (below). here is the ..., You can use np.argsort(np.max(x, axis=0))[-2] . This scales to any index you want by changing the slicing index from -2 to -index .,a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]). ,a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]). ,a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]). ,a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]). ,a = np.arange(6).reshape(2,3) + 10 >>> a array([[10, 11, 12], [13, 14, 15]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) ... ,More generally, np.take_along_axis(a, index_array, axis=a) always yields the ... x = np.array([3, 1, 2]) >>> np.argsort(x) array([1, 2, 0]). Two-dimensional array:. ,In [1]: import numpy as np In [2]: arr = np.array([1, 3, 2, 4, 5]) In [3]: ..... 1, 5, 5, 2, 3, 2, 4, 1, 0]) >>> B = np.zeros(3, int) >>> for i in xrange(3): ... idx = np.argmax(A) .
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np argmax second 相關參考資料
How do I get indices of N maximum values in a NumPy array? - Stack ...
In [1]: import numpy as np In [2]: arr = np.array([1, 3, 2, 4, 5]) In [3]: ..... 1, 5, 5, 2, 3, 2, 4, 1, 0]) >>> B = np.zeros(3, int) >>> for i in xrange(3): ... idx = np.argmax(A) .... https://stackoverflow.com Next argmax values in python - Stack Overflow
Use the command np.argsort(a, axis=-1, kind='quicksort', order=None) , but with appropriate choice of arguments (below). here is the ... https://stackoverflow.com Numpy get index of row with second-largest value - Stack Overflow
You can use np.argsort(np.max(x, axis=0))[-2] . This scales to any index you want by changing the slicing index from -2 to -index . https://stackoverflow.com numpy.argmax — NumPy v1.10 Manual
a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]... https://docs.scipy.org numpy.argmax — NumPy v1.13 Manual
a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]... https://docs.scipy.org numpy.argmax — NumPy v1.14 Manual
a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]... https://docs.scipy.org numpy.argmax — NumPy v1.15 Manual
a = np.arange(6).reshape(2,3) >>> a array([[0, 1, 2], [3, 4, 5]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1) array([2, 2]... https://docs.scipy.org numpy.argmax — NumPy v1.16 Manual
a = np.arange(6).reshape(2,3) + 10 >>> a array([[10, 11, 12], [13, 14, 15]]) >>> np.argmax(a) 5 >>> np.argmax(a, axis=0) array([1, 1, 1]) >>> np.argmax(a, axis=1)&n... https://docs.scipy.org numpy.argsort — NumPy v1.16 Manual
More generally, np.take_along_axis(a, index_array, axis=a) always yields the ... x = np.array([3, 1, 2]) >>> np.argsort(x) array([1, 2, 0]). Two-dimensional array:. https://docs.scipy.org python - How do I get indices of N maximum values in a NumPy array ...
In [1]: import numpy as np In [2]: arr = np.array([1, 3, 2, 4, 5]) In [3]: ..... 1, 5, 5, 2, 3, 2, 4, 1, 0]) >>> B = np.zeros(3, int) >>> for i in xrange(3): ... idx = np.argmax(A) .... https://stackoverflow.com |