python list find all index
You might use something like ind = [[i for i, value in enumerate(lst) if value == x] for x in lst2]. I don't know a purpose of this operation, but it might ...,[(i,j) for i,row in enumerate(hiddenfield) for j,elem in enumerate(row) if elem == 'M']. , In Python, you wouldn't use indexes for this at all, but just deal with the values— [value for value in a if value > 2] . Usually dealing with indexes ..., You are using .index() which will only find the first occurrence of your value in the list. So if you have a value 1.0 at index 2, and at index 9, then ...,>>> l = [1,2,3,1,1] >>> [index for index, value in enumerate(l) if value == 1] [0, 3, 4]. , Use the fact that empty sequences are false in a boolean context, together with a list comprehension: >>> mylist = [[1,2,3,4], [] , [1,2,3,4] ..., NEVER EVER use default data structure e.g. list , dict as variables. This should do it: from collections import defaultdict # Create a dict with ..., You can use a list comprehension: indices = [i for i, x in enumerate(my_list) if x == "whatever"].
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 python list find all index 相關參考資料
Find all index of list containing a value Python - Stack Overflow
You might use something like ind = [[i for i, value in enumerate(lst) if value == x] for x in lst2]. I don't know a purpose of this operation, but it might ... https://stackoverflow.com Finding all indexes of a list of lists in python - Stack Overflow
[(i,j) for i,row in enumerate(hiddenfield) for j,elem in enumerate(row) if elem == 'M']. https://stackoverflow.com Finding the index of elements based on a condition using python ...
In Python, you wouldn't use indexes for this at all, but just deal with the values— [value for value in a if value > 2] . Usually dealing with indexes ... https://stackoverflow.com Finding the indices of matching elements in list in Python - Stack ...
You are using .index() which will only find the first occurrence of your value in the list. So if you have a value 1.0 at index 2, and at index 9, then ... https://stackoverflow.com Get all indexes for a python list - Stack Overflow
>>> l = [1,2,3,1,1] >>> [index for index, value in enumerate(l) if value == 1] [0, 3, 4]. https://stackoverflow.com How to find all indexes of a list that are empty in Python - Stack ...
Use the fact that empty sequences are false in a boolean context, together with a list comprehension: >>> mylist = [[1,2,3,4], [] , [1,2,3,4] ... https://stackoverflow.com How to find all the indexes of a recurring item in a list? (Python ...
NEVER EVER use default data structure e.g. list , dict as variables. This should do it: from collections import defaultdict # Create a dict with ... https://stackoverflow.com python - How to find all occurrences of an element in a list ...
You can use a list comprehension: indices = [i for i, x in enumerate(my_list) if x == "whatever"]. https://stackoverflow.com |