php create table if not exists
table does not exist</p>"; $query = "CREATE TABLE IF NOT EXISTS WEIGHIN_DATA ( id INT ... <?php session_start(); error_reporting(E_ALL); ..., You should get a warning, not an error. What version are you running? Anyway if you want to display erros type this before your SQL query: ..., Try this $query = "SELECT ID FROM USERS"; $result = mysqli_query($dbConnection, $query); if(empty($result)) $query = "CREATE TABLE ..., Your SQL instruction should be: $sql = "CREATE TABLE IF NOT EXISTS $table ( id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY, ..., The query will look like. CREATE TABLE IF NOT EXISTS tbl_user ( id INT NOT NULL AUTO_INCREMENT, PRIMARY KEY(id), uname ...,NOT NULL - Each row must contain a value for that column, null values are not allowed; DEFAULT value - Set a default value that is added when no other value is ... ,php"); $tbl_users = "CREATE TABLE IF NOT EXISTS users ( id INT(11) NOT NULL AUTO_INCREMENT, username VARCHAR(16) NOT NULL, email VARCHAR( ... ,CREATE TABLE IF NOT EXISTS tasks ( task_id INT AUTO_INCREMENT PRIMARY KEY, subject VARCHAR (255) DEFAULT NULL, start_date DATE DEFAULT ... ,A variable in a single quoted string will not be parsed. However, it will be parsed in a double-quoted string: "CREATE TABLE IF NOT EXISTS $tabla ( `ID` int(2) ...
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 php create table if not exists 相關參考資料
create mysql table if it doesn't exist - Stack Overflow
table does not exist</p>"; $query = "CREATE TABLE IF NOT EXISTS WEIGHIN_DATA ( id INT ... <?php session_start(); error_reporting(E_ALL); ... https://stackoverflow.com CREATE TABLE IF NOT EXISTS failing when the table exists ...
You should get a warning, not an error. What version are you running? Anyway if you want to display erros type this before your SQL query: ... https://stackoverflow.com CREATE TABLE IF NOT EXISTS fails with table already exists ...
Try this $query = "SELECT ID FROM USERS"; $result = mysqli_query($dbConnection, $query); if(empty($result)) $query = "CREATE TABLE ... https://stackoverflow.com mysqli and php creating a table that doesn't exist - Stack ...
Your SQL instruction should be: $sql = "CREATE TABLE IF NOT EXISTS $table ( id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY, ... https://stackoverflow.com php - check if database and table exists, if not, create it - Stack ...
The query will look like. CREATE TABLE IF NOT EXISTS tbl_user ( id INT NOT NULL AUTO_INCREMENT, PRIMARY KEY(id), uname ... https://stackoverflow.com PHP MySQL Create Table - W3Schools
NOT NULL - Each row must contain a value for that column, null values are not allowed; DEFAULT value - Set a default value that is added when no other value is ... https://www.w3schools.com PHP MySQL Database Tables Creation Script Logic
php"); $tbl_users = "CREATE TABLE IF NOT EXISTS users ( id INT(11) NOT NULL AUTO_INCREMENT, username VARCHAR(16) NOT NULL, email VARCHAR( ... https://www.developphp.com PHP MySQL: Create A New Table - MySQL Tutorial
CREATE TABLE IF NOT EXISTS tasks ( task_id INT AUTO_INCREMENT PRIMARY KEY, subject VARCHAR (255) DEFAULT NULL, start_date DATE DEFAULT ... https://www.mysqltutorial.org variable name into CREATE TABLE IF NOT EXISTS on php ...
A variable in a single quoted string will not be parsed. However, it will be parsed in a double-quoted string: "CREATE TABLE IF NOT EXISTS $tabla ( `ID` int(2) ... https://stackoverflow.com |