startactivity package name
<category android:name="android.intent.category. ... startActivity(it); ... does not contain such an activity, or if <em>packageName</em> is not,Android 透過Package Name 進行App 執行、開啟應用程式資訊、開啟Google Play ... ACTION_APPLICATION_DETAILS_SETTINGS, uri ); startActivity( intent );. , 如果packageName存在返回入口Intent， startActivity(Intent)可以启动应用，否则返回nullimport android.app.Activity;. 下面有个小示例：.,Launch another app using an intent with package name if app has a launcher activity or using package name and class name of ... startActivity(launchIntent);. , Settings")); startActivity(intent);. If you do not know what Activity you have to open,you can find it's name and it's package name as I mentioned ..., setComponent(new ComponentName("packagename whos activity u want to launch","classname.java")); startActivity(intent);., getLaunchIntentForPackage("com.example.abc"); startActivity( ... If you don't know the package name of application that you wanted to launch ..., As you know the package name of the other app and can't add any intent filter to the destination app, then you should use ... startActivity(intent);., You said your package name (in the manifest) is "neelay.mediaplayer.beatbox". In that case you need to change this: intent.,另一種方式，則是當我們已知B 程式的Package Name 與要啟動的Class Name，則直接在A 程式中，將Package Name 與Class Name 透過intent 的setComponent() ...
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 startactivity package name 相關參考資料
Android 必知必会- 使用Intent 打开第三方应用及验证可用性 ...
<category android:name="android.intent.category. ... startActivity(it); ... does not contain such an activity, or if <em>packageName</em> is not https://likfe.com Android 透過Package Name 進行App 執行、開啟 ... - 昭佑.天翔
Android 透過Package Name 進行App 執行、開啟應用程式資訊、開啟Google Play ... ACTION_APPLICATION_DETAILS_SETTINGS, uri ); startActivity( intent );. https://tomkuo139.blogspot.com Android启动另一个应用(只需知道package name) - garybook的 ...
如果packageName存在返回入口Intent， startActivity(Intent)可以启动应用，否则返回nullimport android.app.Activity;. 下面有个小示例：. https://blog.csdn.net Launch another app using an intent with package name if app ...
Launch another app using an intent with package name if app has a launcher activity or using package name and class name of ... startActivity(launchIntent);. https://gist.github.com Start Activity Android with class name - Stack Overflow
Settings")); startActivity(intent);. If you do not know what Activity you have to open,you can find it's name and it's package name as I mentioned ... https://stackoverflow.com Start activity from another package - Stack Overflow
setComponent(new ComponentName("packagename whos activity u want to launch","classname.java")); startActivity(intent);. https://stackoverflow.com start application knowing package name - Stack Overflow
getLaunchIntentForPackage("com.example.abc"); startActivity( ... If you don't know the package name of application that you wanted to launch ... https://stackoverflow.com Starting activity from another application using only package name ...
As you know the package name of the other app and can't add any intent filter to the destination app, then you should use ... startActivity(intent);. https://stackoverflow.com Unable to start activity by using the package name - Stack Overflow
You said your package name (in the manifest) is "neelay.mediaplayer.beatbox". In that case you need to change this: intent. https://stackoverflow.com 《Android》『呼叫外部App』- 透過startActivity 執行外部App 的 ...
另一種方式，則是當我們已知B 程式的Package Name 與要啟動的Class Name，則直接在A 程式中，將Package Name 與Class Name 透過intent 的setComponent() ... https://xnfood.com.tw |