python3 reduce is not defined
from contextlib import contextmanager @contextmanager def noiters(*funcs): if not funcs: funcs = [map, filter, zip] # etc from functools import reduce globals()[reduce.__name__] = reduce for func in funcs: globals()[func.__name__] = lambda *ar, func = fu, xor = lambda x,y: (x+y)%2 l = reduce(xor, [1,2,3,4]). And got the following error: l = reduce(xor, [1,2,3,4]) NameError: name 'reduce' is not defined. Tried printing reduce into interactive console - got this error: NameError: name 'reduce, I'm going to guess that: You are using Python 3, and; You are following a tutorial designed for Python 2. The reduce function, since it is not commonly used, was removed from the built-in functions in Python 3. It is still available in the functools , I'm going to guess that: You are using Python 3, and; You are following a tutorial designed for Python 2. The reduce function, since it is not commonly used, was removed from the built-in functions in Python 3. It is still available in the functools , GitHub is where people build software. More than 27 million people use GitHub to discover, fork, and contribute to over 80 million projects.,今天在搜用Python求阶乘的时候, 搜出来的最简单的是用reduce这个built-in function, 但是我在用reduce的时候, 却报NameError: name 'reduce' is not defined. 于是又搜了一下,发现在python 3.0.0.0以后, reduce已经不在built-in function里了, 要用它就得from functools imp. ,今天在搜用python求阶乘的时候, 搜出来的最简单的是用reduce这个built-in function, 但是我在用reduce的时候, 却报NameError: name reduce is not defined. 于是又搜了一下,发现在python 3.0.0.0以后, reduce已经不在built-in function里了, 要用它就得from functools impor. ,问题来了使用reduce() 测试的时候报错：reduce 未定义！print(reduce(lambda x, y: x + y, [ 1, 2, 3]))"""Output： NameError: name 'reduce' is not defined """解决引用stackoverflow的回答： - 你使用的是python3 - 参考的是python2的指南from.
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 python3 reduce is not defined 相關參考資料
How to use filter, map, and reduce in Python 3 - Stack Overflow
from contextlib import contextmanager @contextmanager def noiters(*funcs): if not funcs: funcs = [map, filter, zip] # etc from functools import reduce globals()[reduce.__name__] = reduce for func in ... https://stackoverflow.com NameError: name 'reduce' is not defined in Python - Stack Overflow
xor = lambda x,y: (x+y)%2 l = reduce(xor, [1,2,3,4]). And got the following error: l = reduce(xor, [1,2,3,4]) NameError: name 'reduce' is not defined. Tried printing reduce into interactive c... https://stackoverflow.com python - NameError: global name 'reduce' is not defined - Stack ...
I'm going to guess that: You are using Python 3, and; You are following a tutorial designed for Python 2. The reduce function, since it is not commonly used, was removed from the built-in functio... https://stackoverflow.com python - NameError: global name 'reduce' is not defined - Stack Overflow
I'm going to guess that: You are using Python 3, and; You are following a tutorial designed for Python 2. The reduce function, since it is not commonly used, was removed from the built-in functio... https://stackoverflow.com Python 3 - 'reduce' is not defined · Issue #374 · sehmaschinedjango ...
GitHub is where people build software. More than 27 million people use GitHub to discover, fork, and contribute to over 80 million projects. https://github.com Python NameError: name 'reduce' is not defined - CSDN博客
今天在搜用Python求阶乘的时候, 搜出来的最简单的是用reduce这个built-in function, 但是我在用reduce的时候, 却报NameError: name 'reduce' is not defined. 于是又搜了一下,发现在python 3.0.0.0以后, reduce已经不在built-in function里了, 要用它就得from functoo... https://blog.csdn.net Python的reduce - CSDN博客
今天在搜用python求阶乘的时候, 搜出来的最简单的是用reduce这个built-in function, 但是我在用reduce的时候, 却报NameError: name reduce is not defined. 于是又搜了一下,发现在python 3.0.0.0以后, reduce已经不在built-in function里了, 要用它就得from functools impor. https://blog.csdn.net Python编程：NameError: name 'reduce' is not defined - CSDN博客
问题来了使用reduce() 测试的时候报错：reduce 未定义！print(reduce(lambda x, y: x + y, [ 1, 2, 3]))"""Output： NameError: name 'reduce' is not defined """解决引用stackoverflow的回答： - 你使用的是... https://blog.csdn.net |