python replace list in list
Beside list comprehension, you can try map ... In [1]: words = [str(i) for i in range(10000)] In [2]: %timeit replaced = [w.replace('1', '<1>') for w in ...,>>> a= [1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1] >>> for n, i in enumerate(a): ... if i == 1: ... a[n] = 10 ... >>> a [10, 2, 3, 4, 5, 10, 2, 3, 4, 5, 10]. , There's nothing built-in, but it's just a loop to do the replacement in-place: for i, word in enumerate(words): if word == 'chicken': words[i] ..., The problem is that you are creating a copy of the list and then modifying the copy. What you want to do is modify the original list. Try this ..., lst = [6,13,22,40] lst = [i for i in map(lambda arg: arg[1] if arg[0] ==0 else lst[arg[0]]-lst[arg[0]-1], enumerate(lst) )], You need to break for look as soon as you find the necessary element: item = [1,2,3,4,5,6,7,8,9] for element in item: if element not in z: print ..., You're using the .replace() method on each element of the list as though it were a string. But each element of this list is another list! You don't ..., Because str.replace doesn't work in-place, it returns a copy. As immutable objects, you need to assign the strings to elements in your list of lists.,You can modify the original list in-place if you want, but it doesn't actually save time: ... Here are (Python 3.6.3) timings demonstrating the non-timesave:
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 python replace list in list 相關參考資料
Find and replace string values in list - Stack Overflow
Beside list comprehension, you can try map ... In [1]: words = [str(i) for i in range(10000)] In [2]: %timeit replaced = [w.replace('1', '<1>') for w in ... https://stackoverflow.com finding and replacing elements in a list (python) - Stack Overflow
>>> a= [1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1] >>> for n, i in enumerate(a): ... if i == 1: ... a[n] = 10 ... >>> a [10, 2, 3, 4, 5, 10, 2, 3, 4, 5, 10]. https://stackoverflow.com Is there a method like .replace() for list in python? - Stack Overflow
There's nothing built-in, but it's just a loop to do the replacement in-place: for i, word in enumerate(words): if word == 'chicken': words[i] ... https://stackoverflow.com Python - How to change values in a list of lists? - Stack Overflow
The problem is that you are creating a copy of the list and then modifying the copy. What you want to do is modify the original list. Try this ... https://stackoverflow.com Python list: how can I replace certain items of the list? - Quora
lst = [6,13,22,40] lst = [i for i in map(lambda arg: arg[1] if arg[0] ==0 else lst[arg[0]]-lst[arg[0]-1], enumerate(lst) )] https://www.quora.com Python: Replacing item in a list of lists - Stack Overflow
You need to break for look as soon as you find the necessary element: item = [1,2,3,4,5,6,7,8,9] for element in item: if element not in z: print ... https://stackoverflow.com Replace a string in list of lists - Stack Overflow
You're using the .replace() method on each element of the list as though it were a string. But each element of this list is another list! You don't ... https://stackoverflow.com Replace elements in a list of lists python - Stack Overflow
Because str.replace doesn't work in-place, it returns a copy. As immutable objects, you need to assign the strings to elements in your list of lists. https://stackoverflow.com Replace values in list using Python - Stack Overflow
You can modify the original list in-place if you want, but it doesn't actually save time: ... Here are (Python 3.6.3) timings demonstrating the non-timesave: https://stackoverflow.com |