python list sort index
You can use the python sorting functions' key parameter to sort the index array instead. >>> s = [2, 3, 1, 4, 5] >>> sorted(range(len(s)), key=lambda k: s[k]) [2, 0, 1, 3, 4] >>> ..., >>> a = [1,4,6,2,3] >>> [b[0] for b in sorted(enumerate(a),key=lambda i:i[1])] [0, 3, 4, 1, 2]. Explanation: enumerate(a) returns an enumeration over tuples consisting of the indexes and values in the original list: [(0, 1), (1, 4), (2,, If you are using numpy, you have the argsort() function available: >>> import numpy >>> numpy.argsort(myList) array([0, 1, 2, 4, 3]). http://docs.scipy.org/doc/numpy/reference/generated/numpy.argsort.html. This returns the arguments tha, You could always call argsort twice: >>> a.argsort().argsort() array([0, 3, 1, 2]). As far as I know, there's no "double-argsort" function available in NumPy, but applying argsort twice to an array is a common way to calculate the , If you are using numpy, you have the argsort() function available: >>> import numpy >>> numpy.argsort(myList) array([0, 1, 2, 4, 3]). http://docs.scipy.org/doc/numpy/reference/generated/numpy.argsort.html. This returns the arguments tha, You could use sorted() on a slice and then assign the result back to the slice: al[2:] = sorted(al[2:]) ..., This is a job for itemgetter >>> from operator import itemgetter >>> L=[[0, 1, 'f'], [4, 2, 't'], [9, 4, 'afsd']] >>> sorted(L, key=itemgetter(2)) [[9, 4, 'afsd'], [0, 1, 'f'], [4, 2, , This is a job for itemgetter >>> from operator import itemgetter >>> L=[[0, 1, 'f'], [4, 2, 't'], [9, 4, 'afsd']] >>> sorted(L, key=itemgetter(2)) [[9, 4, 'afsd'], [0, 1, 'f'], [4, 2, , The second stage then sorts these indices in B back into the order 0,1,2,3,4,5 and produces C which contains the index in the list B. It may help to think of B as sorting the list into descending order, and C as reversing the sort back into the original , The lambda returns the fourth element of each of the inner lists and the sorted function uses that to sort those list. This assumes that int(elem) will not fail for the list. Or use itemgetter (As Ashwini's comment pointed out, this method would not
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 python list sort index 相關參考資料
python - how to return index of a sorted list? - Stack Overflow
You can use the python sorting functions' key parameter to sort the index array instead. >>> s = [2, 3, 1, 4, 5] >>> sorted(range(len(s)), key=lambda k: s[k]) [2, 0, 1, 3, 4] &g... https://stackoverflow.com python - Sort a list then give the indexes of the elements in ...
>>> a = [1,4,6,2,3] >>> [b[0] for b in sorted(enumerate(a),key=lambda i:i[1])] [0, 3, 4, 1, 2]. Explanation: enumerate(a) returns an enumeration over tuples consisting of the indexe... https://stackoverflow.com indexing - How to get indices of a sorted array in Python - Stack ...
If you are using numpy, you have the argsort() function available: >>> import numpy >>> numpy.argsort(myList) array([0, 1, 2, 4, 3]). http://docs.scipy.org/doc/numpy/reference/gener... https://stackoverflow.com sorting - How to get the index of the sorted list for the original ...
You could always call argsort twice: >>> a.argsort().argsort() array([0, 3, 1, 2]). As far as I know, there's no "double-argsort" function available in NumPy, but applying args... https://stackoverflow.com indexing - How to get indices of a sorted array in Python - Stack Overflow
If you are using numpy, you have the argsort() function available: >>> import numpy >>> numpy.argsort(myList) array([0, 1, 2, 4, 3]). http://docs.scipy.org/doc/numpy/reference/gener... https://stackoverflow.com Sort list from a specific index value in python - Stack Overflow
You could use sorted() on a slice and then assign the result back to the slice: al[2:] = sorted(al[2:]) ... https://stackoverflow.com python - How to sort a list of lists by a specific index of the ...
This is a job for itemgetter >>> from operator import itemgetter >>> L=[[0, 1, 'f'], [4, 2, 't'], [9, 4, 'afsd']] >>> sorted(L, key=itemgetter(2)) [... https://stackoverflow.com python - How to sort a list of lists by a specific index of the inner list ...
This is a job for itemgetter >>> from operator import itemgetter >>> L=[[0, 1, 'f'], [4, 2, 't'], [9, 4, 'afsd']] >>> sorted(L, key=itemgetter(2)) [... https://stackoverflow.com Finding the Index of sorted elements in Python Array - Stack Overflow
The second stage then sorts these indices in B back into the order 0,1,2,3,4,5 and produces C which contains the index in the list B. It may help to think of B as sorting the list into descending ord... https://stackoverflow.com Python - How to sort a list of lists by the fourth element in each list ...
The lambda returns the fourth element of each of the inner lists and the sorted function uses that to sort those list. This assumes that int(elem) will not fail for the list. Or use itemgetter (As As... https://stackoverflow.com |