python list row to column
List comprehensions are your friend when working with lists of lists: ... a handy 'idiom' for transposing a nested list, turning 'columns' into 'rows':, You are first adding R0Cx and then R1Cxy . You need to add RxCy . So try: newlist = [] row = A col = B for x in range (0, row): newlist.append([]) ..., You can use zip to transpose the data: arr = [[13, 4, 8, 14, 1], [9, 6, 3, 7, 21], [5, 12, 17, 9, 3]] new_arr = zip(*arr) # [(13, 9, 5), (4, 6, 12), (8, 3, 17), ..., Normal Python lists are single-dimensional too. However, if you have a ... def column(matrix, i): return [row[i] for row in matrix]. Extracting the ..., you can do it this way: In [84]: df Out[84]: A B 0 some value [[L1, L2]] 1 another value [[L3, L4, L5]] In [85]: (df['B'].apply(lambda x: pd., So if you consider the outer list to be a matrix and the inner tuples to be the rows, that's a transposition (ie., we turned the rows to columns)., You may use zip() for this. Firstly convert your list of string to list of list using str.split() , then iterate over ziped list. Below is the sample code: > ..., strs = ["AAA", "BBB", "CCC"] print map(''.join, zip(*strs)) # for python 3 use: list(map(''.join, zip(*strs))) # thanks @cesar. Output is now a list of ..., Change in you own code: Python 3.x: set(list(zip(*l)[2])). Python 2.x: set(zip(*l)[2]). Demo: l=[['John', '35', 'UK'],['Emma', '43', 'UK'],['Lucy', '25', ...,map(list, zip(*l)) --> [[1, 4, 7], [2, 5, 8], [3, 6, 9]]. For python 3.x users can use .... [list(row) for row in six.moves.zip_longest(*list_list, fillvalue='-')] [[1, 4, 7], [2, 5, 8], [3 ...
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 python list row to column 相關參考資料
arrays - How to access a column in a list of lists in python ...
List comprehensions are your friend when working with lists of lists: ... a handy 'idiom' for transposing a nested list, turning 'columns' into 'rows': https://stackoverflow.com Create a list with certain number of rows and columns in Python ...
You are first adding R0Cx and then R1Cxy . You need to add RxCy . So try: newlist = [] row = A col = B for x in range (0, row): newlist.append([]) ... https://stackoverflow.com python - convert all rows to columns and columns to rows in Arrays ...
You can use zip to transpose the data: arr = [[13, 4, 8, 14, 1], [9, 6, 3, 7, 21], [5, 12, 17, 9, 3]] new_arr = zip(*arr) # [(13, 9, 5), (4, 6, 12), (8, 3, 17), ... https://stackoverflow.com python - How do you extract a column from a multi-dimensional ...
Normal Python lists are single-dimensional too. However, if you have a ... def column(matrix, i): return [row[i] for row in matrix]. Extracting the ... https://stackoverflow.com python - How to convert column with list of values into rows in ...
you can do it this way: In [84]: df Out[84]: A B 0 some value [[L1, L2]] 1 another value [[L3, L4, L5]] In [85]: (df['B'].apply(lambda x: pd. https://stackoverflow.com python - How to do row-to-column transposition of data in csv ...
So if you consider the outer list to be a matrix and the inner tuples to be the rows, that's a transposition (ie., we turned the rows to columns). https://stackoverflow.com python - list organized into columns not rows - Stack Overflow
You may use zip() for this. Firstly convert your list of string to list of list using str.split() , then iterate over ziped list. Below is the sample code: > ... https://stackoverflow.com Python, list of strings, rows into columns - Stack Overflow
strs = ["AAA", "BBB", "CCC"] print map(''.join, zip(*strs)) # for python 3 use: list(map(''.join, zip(*strs))) # thanks @cesar. Output is now a list of&n... https://stackoverflow.com transpose - Extract a column from a list of rows with Python ...
Change in you own code: Python 3.x: set(list(zip(*l)[2])). Python 2.x: set(zip(*l)[2]). Demo: l=[['John', '35', 'UK'],['Emma', '43', 'UK'],['Lucy&#... https://stackoverflow.com Transpose list of lists - Stack Overflow
map(list, zip(*l)) --> [[1, 4, 7], [2, 5, 8], [3, 6, 9]]. For python 3.x users can use .... [list(row) for row in six.moves.zip_longest(*list_list, fillvalue='-')] [[1, 4, 7], [2, 5, 8], [3... https://stackoverflow.com |