python list remove another list
list_1=['a', 'b', 'c', 'd'] list_2=['1', 'e', '1', 'e'] index_list = ['1', '3'] #convert index_list to int index_list = [ int(x) for x in index_list ] #Delete elements as per , Try this: array1 = [1, 2, 3, 4, 5, 6, 7, 8, 9] array2 = [1, 2, 2, 2, 5, 6, 6, 6, 9] set(array1).difference(array2) => set([3, 4, 7, 8]). The above makes use of ..., Here is a non list comprehension version for those new to Python listA = [1, 1, 3, 5, 5, 5, 7] listB = [1, 2, 5, 5, 7] for i in listB: if i in listA: ...,remove() can also perform this task but only if exception of not getting specific element in handled properly. One can iterate for all the elements of remove list and remove those elements from the original list. , While trying to remove a list from another list, I m facing the below issue. element = [['(4.00,4.00)', '(4.00,2.00)'], ['(4.00,4.00)', '(4.00,8.00)'], ...,Python has a language feature called List Comprehensions that is perfectly suited to making this sort of thing extremely easy. The following statement does ... ,>>> a = range(1, 10) >>> [x for x in a if x not in [2, 3, 7]] [1, 4, 5, 6, 8, 9]. , Use list comprehension: >>> list1 ... NOTE: Lookups in lists are O(n) , consider making a set from list2 instead - lookups in sets are O(1) ., You can write this using a list comprehension which tells us quite literally which elements need to end up in new_list : a = ['apple', 'carrot' ..., You have not really posted enough code but from what I can gather: import collections import uuid class Person(): def __init__(self, name="", ...
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 python list remove another list 相關參考資料
How to remove index list from another list in python? - Stack Overflow
list_1=['a', 'b', 'c', 'd'] list_2=['1', 'e', '1', 'e'] index_list = ['1', '3'] #convert index_list to int index_list = ... https://stackoverflow.com Python - Remove a set of a list from another list - Stack Overflow
Try this: array1 = [1, 2, 3, 4, 5, 6, 7, 8, 9] array2 = [1, 2, 2, 2, 5, 6, 6, 6, 9] set(array1).difference(array2) => set([3, 4, 7, 8]). The above makes use of ... https://stackoverflow.com python remove elements of list from another list WITH MULTIPLE ...
Here is a non list comprehension version for those new to Python listA = [1, 1, 3, 5, 5, 5, 7] listB = [1, 2, 5, 5, 7] for i in listB: if i in listA: ... https://stackoverflow.com Python | Remove all values from a list present in other list ...
remove() can also perform this task but only if exception of not getting specific element in handled properly. One can iterate for all the elements of remove list and remove those elements from the or... https://www.geeksforgeeks.org Python.. Removing list from another list - Stack Overflow
While trying to remove a list from another list, I m facing the below issue. element = [['(4.00,4.00)', '(4.00,2.00)'], ['(4.00,4.00)', '(4.00,8.00)'], ... https://stackoverflow.com Remove all the elements that occur in one list from another ...
Python has a language feature called List Comprehensions that is perfectly suited to making this sort of thing extremely easy. The following statement does ... https://stackoverflow.com Remove all values within one list from another list? - Stack ...
>>> a = range(1, 10) >>> [x for x in a if x not in [2, 3, 7]] [1, 4, 5, 6, 8, 9]. https://stackoverflow.com remove elements in one list present in another list - Stack Overflow
Use list comprehension: >>> list1 ... NOTE: Lookups in lists are O(n) , consider making a set from list2 instead - lookups in sets are O(1) . https://stackoverflow.com Remove list from list in Python - Stack Overflow
You can write this using a list comprehension which tells us quite literally which elements need to end up in new_list : a = ['apple', 'carrot' ... https://stackoverflow.com Removing list item if not in another list - python - Stack Overflow
You have not really posted enough code but from what I can gather: import collections import uuid class Person(): def __init__(self, name="", ... https://stackoverflow.com |