python image matrix
Falko's post is certainly the canonical way to do it. However, if I can suggest a more numpy / Pythonic way to do it, I would let the first dimension be the index of which image you want, while the second and third dimensions be the rows and columns , import numpy import Image def PIL2array(img): return numpy.array(img.getdata(), numpy.uint8).reshape(img.size[1], img.size[0], 3) def array2PIL(arr, size): mode = 'RGBA' arr = arr.reshape(arr.shape[0]*arr.shape[1], arr.shape[2]) if len(arr[0]) ==,scipy.misc.imread() will return a Numpy array, which is handy for lots of things. , I'm not quite sure what your end goal is, but try something more like this: import numpy as np import Image import glob filenames = glob.glob('/path/to/your/files/*.pgm') images = [Image.open(fn).convert('L') for fn in filenames] data, You can use numpy.asarray() : >>> import Image, numpy >>> numpy.asarray(Image.open('1.jpg').convert('L')).,It looks like arr is a 2d array. If you want to use x, y as index and arr is a 2d array then try this: m, n = arr.shape for x in range(m): for y in range(n): if arr[x,y] > 1: normal.append(1) else: normal.append(0). However the code doesn't look py,I think what you are looking for is: list(im.getdata()). or, if the image is too big to load entirely into memory, so something like that: for pixel in iter(im.getdata()): print pixel. from PIL documentation: getdata. im.getdata() => sequence. Returns , You may try from pylab import * A = rand(5,5) figure(1) imshow(A, interpolation='nearest') grid(True). enter image description here. source ..., The simplest answer is to use the NumPy and SciPy wrappers around PIL. There's a great tutorial, but the basic idea is: from scipy import misc arr = misc.imread('lena.png') # 640x480x3 array arr[20, 30] # 3-vector for a pixel arr[20, 30, 1] #
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 python image matrix 相關參考資料
arrays - Python - read images into image matrix - Stack Overflow
Falko's post is certainly the canonical way to do it. However, if I can suggest a more numpy / Pythonic way to do it, I would let the first dimension be the index of which image you want, while t... https://stackoverflow.com Conversion of PIL Image and numpy array « Python recipes ...
import numpy import Image def PIL2array(img): return numpy.array(img.getdata(), numpy.uint8).reshape(img.size[1], img.size[0], 3) def array2PIL(arr, size): mode = 'RGBA' arr = arr.reshape(arr... http://code.activestate.com Convert image to a matrix in python - Stack Overflow
scipy.misc.imread() will return a Numpy array, which is handy for lots of things. https://stackoverflow.com numpy - Image to matrix using python - Stack Overflow
I'm not quite sure what your end goal is, but try something more like this: import numpy as np import Image import glob filenames = glob.glob('/path/to/your/files/*.pgm') images = [Image.... https://stackoverflow.com numpy - Python get image matrix PIL - Stack Overflow
You can use numpy.asarray() : >>> import Image, numpy >>> numpy.asarray(Image.open('1.jpg').convert('L')). https://stackoverflow.com opencv - Image to matrix in python - Stack Overflow
It looks like arr is a 2d array. If you want to use x, y as index and arr is a 2d array then try this: m, n = arr.shape for x in range(m): for y in range(n): if arr[x,y] > 1: normal.append(1) else:... https://stackoverflow.com PIL image to array (numpy array to array) - Python - Stack Overflow
I think what you are looking for is: list(im.getdata()). or, if the image is too big to load entirely into memory, so something like that: for pixel in iter(im.getdata()): print pixel. from PIL docume... https://stackoverflow.com python - convert matrix to image - Stack Overflow
You may try from pylab import * A = rand(5,5) figure(1) imshow(A, interpolation='nearest') grid(True). enter image description here. source ... https://stackoverflow.com python - RGB matrix of an image - Stack Overflow
The simplest answer is to use the NumPy and SciPy wrappers around PIL. There's a great tutorial, but the basic idea is: from scipy import misc arr = misc.imread('lena.png') # 640x480x3 ar... https://stackoverflow.com |