python find multiple index
There are many method to achieve that, using index() etc. But sometimes require to find all the indices of a particular value in case it has multiple occurrences in ... , In this tutorial, you will learn exclusively about the index() function. ... For more on list comprehension, check out DataCamp's Python List ..., Using regular expressions, you can use re.finditer to find all (non-overlapping) ... you can also repeatedly use str.find to get the next index:, simple python loop was the quickest with lambda operation a close second, ... One trivial way to find elements would be as follows: a = [-2, 1, 5, ..., you may try this: In [378]: (a1[:, None] == a2).argmax(axis=0) Out[378]: array([4, 5, 1, 2, 8], dtype=int64)., Sounds like a one-liner Python is able to do! [i for i, j in enumerate(myList) if 'how' in j.lower() or 'what' in j.lower()].,>>> l = [1,2,3,1,1] >>> [index for index, value in enumerate(l) if value == 1] [0, 3, 4]. , def getWord(string, word): index = 0 data = [] for i in string.split(' '): if i.lower() ... It seems that you're trying to find occurrences of a word inside a ..., N = [] for i in range(len(L)): if L[i] in R: N.append(i). or with a generator. N = [i for i in range(len(L)) if L[i] in R]. or with arrays import numpy as np ..., indices = [i for i, x in enumerate(my_list) if x == "whatever"] .... A solution using list.index : def indices(lst .... Or Use range (python 3): l=[i for i in ...
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 python find multiple index 相關參考資料
Python | Ways to find indices of value in list - GeeksforGeeks
There are many method to achieve that, using index() etc. But sometimes require to find all the indices of a particular value in case it has multiple occurrences in ... https://www.geeksforgeeks.org Python List Index() (article) - DataCamp
In this tutorial, you will learn exclusively about the index() function. ... For more on list comprehension, check out DataCamp's Python List ... https://www.datacamp.com Finding multiple occurrences of a string within a string in Python ...
Using regular expressions, you can use re.finditer to find all (non-overlapping) ... you can also repeatedly use str.find to get the next index: https://stackoverflow.com Access multiple elements of list knowing their index - Stack Overflow
simple python loop was the quickest with lambda operation a close second, ... One trivial way to find elements would be as follows: a = [-2, 1, 5, ... https://stackoverflow.com Find index of multiple elements in numpy array - Stack Overflow
you may try this: In [378]: (a1[:, None] == a2).argmax(axis=0) Out[378]: array([4, 5, 1, 2, 8], dtype=int64). https://stackoverflow.com finding index of multiple items in a list - Stack Overflow
Sounds like a one-liner Python is able to do! [i for i, j in enumerate(myList) if 'how' in j.lower() or 'what' in j.lower()]. https://stackoverflow.com Get all indexes for a python list - Stack Overflow
>>> l = [1,2,3,1,1] >>> [index for index, value in enumerate(l) if value == 1] [0, 3, 4]. https://stackoverflow.com How can I find and print the indexes of multiple elements in a ...
def getWord(string, word): index = 0 data = [] for i in string.split(' '): if i.lower() ... It seems that you're trying to find occurrences of a word inside a ... https://stackoverflow.com Finding the Indices of multiple items in a list, using a list ...
N = [] for i in range(len(L)): if L[i] in R: N.append(i). or with a generator. N = [i for i in range(len(L)) if L[i] in R]. or with arrays import numpy as np ... https://stackoverflow.com How to find all occurrences of an element in a list? - Stack Overflow
indices = [i for i, x in enumerate(my_list) if x == "whatever"] .... A solution using list.index : def indices(lst .... Or Use range (python 3): l=[i for i in ... https://stackoverflow.com |