python class nameerror name is not defined
当初学Python 时，想要弄懂Python 的错误信息的含义可能有点复杂。 ... else , for , while , class , def 声明末尾添加：（导致SyntaxError ：invalid syntax ） ... 8）变量或者函数名拼写错误（导致“NameError: name 'fooba' is not defined”）., Why not define it inside the class, maybe within __init__ and use it? ... import csv class Pitch: def __init__(self, name, result, spreadsheet): ..., As I said in my comment, When you call for i in customers: , customers is not in scope of that function. I just wanted to add also, that you use,1 Answer. The problem is that your if __name__ == "__main__" block is inside of your class definition. This will cause an error, as the code within the if will be run as part of the class being created, before the class been bound to a name. , Forward declaration doesn't work in Python. So you'll get an error only if you create an object of the Main class as follows: class Main: def ..., You need to make an instance of the class to use its methods first: client = Client('192.168.1.94','root','root') client.addClient('192.168.1.95' ..., If you want your variables to be visible within the scope of your class functions, pass self into every class function and use your class variables ..., The variable options is likely intended to maintain a reference to the available options. What it's doing instead is calling the method itself before ..., Your code is correct, but I suspect there is something wrong with the indentation. This is how it should be class Agent: def hello(self, ..., Define the class before you use it: class Something: def out(self): print("it works") s = Something() s.out(). You need to pass self as the first ...
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17个新手常见Python运行时错误_织梦CMS
当初学Python 时，想要弄懂Python 的错误信息的含义可能有点复杂。 ... else , for , while , class , def 声明末尾添加：（导致SyntaxError ：invalid syntax ） ... 8）变量或者函数名拼写错误（导致“NameError: name 'fooba' is not defined”）. http://www.dedecms.com How to fix "Class name is not defined" error in Python? - Stack ...
Why not define it inside the class, maybe within __init__ and use it? ... import csv class Pitch: def __init__(self, name, result, spreadsheet): ... https://stackoverflow.com Class Variable NameError not defined python - Stack Overflow
As I said in my comment, When you call for i in customers: , customers is not in scope of that function. I just wanted to add also, that you use https://stackoverflow.com python className not defined NameError - Stack Overflow
1 Answer. The problem is that your if __name__ == "__main__" block is inside of your class definition. This will cause an error, as the code within the if will be run as part of the class be... https://stackoverflow.com NameError: name 'Class' is not defined - Stack Overflow
Forward declaration doesn't work in Python. So you'll get an error only if you create an object of the Main class as follows: class Main: def ... https://stackoverflow.com Name is not defined in Python - Stack Overflow
You need to make an instance of the class to use its methods first: client = Client('192.168.1.94','root','root') client.addClient('192.168.1.95' ... https://stackoverflow.com Python class NameError. Var is not defined - Stack Overflow
If you want your variables to be visible within the scope of your class functions, pass self into every class function and use your class variables ... https://stackoverflow.com Python NameError: name '...' is not defined in a class - Stack ...
The variable options is likely intended to maintain a reference to the available options. What it's doing instead is calling the method itself before ... https://stackoverflow.com NameError: class name is not defined - Stack Overflow
Your code is correct, but I suspect there is something wrong with the indentation. This is how it should be class Agent: def hello(self, ... https://stackoverflow.com Python NameError: name is not defined - Stack Overflow
Define the class before you use it: class Something: def out(self): print("it works") s = Something() s.out(). You need to pass self as the first ... https://stackoverflow.com |