php check datetime format

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php check datetime format

checkdate — Validate a Gregorian date ... <?php function validateDate($date, $format = 'Y-m-d H:i:s') $d = DateTime::createFromFormat($format, $date); ,2014年6月25日 — You can use DateTime::createFromFormat() for this purpose: ... <?php function validateDateTime($dateStr, $format) ... The easiest way to check if given date is valid probably converting it to unixtime using strtotime , formatting ...,(PHP 5 >= 5.2.1, PHP 7). DateTime::format -- DateTimeImmutable::format -- DateTimeInterface::format -- date_format — Returns date formatted according to ... ,2015年12月3日 — You can try DateTime::createFromFormat('Y-m-d H:i:s', '2038-01-19 ... the class seems to only validate the format, a date like 2015-18-39 is still ... ,2015年5月21日 — function validateDate($date, $format = 'Y-m-d H:i:s') $d = DateTime::createFromFormat($format, ... This expression is true if $myVar is a PHP DateTime object. ... The simplest answer is : to check with strtotime() function ,2011年8月18日 — php function isValidDateTime($dateTime) if (preg_match("/^(-d4})-(-d2})-(-d2}) ([01][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$/", $dateTime, $matches)) if (checkdate($matches[2], $matches[3], $matches[1])) return true; } } return ,function validateDate($date) $format = 'Y-m-d h:i A'; // Eg : 2014-09-24 10:19 PM $dateTime = DateTime::createFromFormat($format, $date); if ($dateTime ... ,2012年11月2日 — $dt = DateTime::createFromFormat("Y-m-d", $date); return $dt !== false && !array_sum($dt::getLastErrors());. This validates the input too: $dt !== ,2017年11月7日 — I've extended the method with a strict check option: ... The PHP codes states: ... $f = DateTime::createFromFormat($format, $date); $valid ...

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php check datetime format 相關參考資料
checkdate - Manual - PHP

checkdate — Validate a Gregorian date ... &lt;?php function validateDate($date, $format = &#39;Y-m-d H:i:s&#39;) $d = DateTime::createFromFormat($format, $date);

https://www.php.net

Correctly determine if date string is a valid date in that format ...

2014年6月25日 — You can use DateTime::createFromFormat() for this purpose: ... &lt;?php function validateDateTime($dateStr, $format) ... The easiest way to check if given date is valid probably converti...

https://stackoverflow.com

DateTime::format - Manual - PHP

(PHP 5 &gt;= 5.2.1, PHP 7). DateTime::format -- DateTimeImmutable::format -- DateTimeInterface::format -- date_format — Returns date formatted according to&nbsp;...

https://www.php.net

Fast way in PHP to check if a value is in MySQL datetime ...

2015年12月3日 — You can try DateTime::createFromFormat(&#39;Y-m-d H:i:s&#39;, &#39;2038-01-19 ... the class seems to only validate the format, a date like 2015-18-39 is still&nbsp;...

https://stackoverflow.com

how can I check if a variable type is DateTime - Stack Overflow

2015年5月21日 — function validateDate($date, $format = &#39;Y-m-d H:i:s&#39;) $d = DateTime::createFromFormat($format, ... This expression is true if $myVar is a PHP DateTime object. ... The simplest a...

https://stackoverflow.com

How to check string&#39;s date format in PHP? - Stack Overflow

2011年8月18日 — php function isValidDateTime($dateTime) if (preg_match(&quot;/^(-d4})-(-d2})-(-d2}) ([01][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$/&quot;, $dateTime, $matches)) if (checkdate($matches[2...

https://stackoverflow.com

php check if valid date and time - Stack Overflow

function validateDate($date) $format = &#39;Y-m-d h:i A&#39;; // Eg : 2014-09-24 10:19 PM $dateTime = DateTime::createFromFormat($format, $date); if ($dateTime&nbsp;...

https://stackoverflow.com

PHP Regex to check date is in YYYY-MM-DD format - Stack ...

2012年11月2日 — $dt = DateTime::createFromFormat(&quot;Y-m-d&quot;, $date); return $dt !== false &amp;&amp; !array_sum($dt::getLastErrors());. This validates the input too: $dt !==

https://stackoverflow.com

Verify valid date using PHP&#39;s DateTime class - Stack Overflow

2017年11月7日 — I&#39;ve extended the method with a strict check option: ... The PHP codes states: ... $f = DateTime::createFromFormat($format, $date); $valid&nbsp;...

https://stackoverflow.com