oracle sql split string into columns
Splitting into rows or columns.... very commonly asked question on these forums... SQL> ed Wrote file afiedt.buf 1 with t as (select 'abcd,123 ... ,Since it a single row, you need to first split the string into multiple rows using new line character as delimiter. And then, you could do it using simple SUBSTR and ... , REGEXP_SUBSTR to the rescue! with sample_data as (select 'p1.pm.100' charge_num, '1.1.1,1000' mapping_col from dual union all select ...,I want to split the strings into two columns so that the records are at 'Level2' ... select id, regexp_substr(string,'[^,]+', 1, level) AS level1_flat from test connect by ... ,I want to split the strings into two columns so that the records are at 'Level2' ... select id, regexp_substr(string,'[^,]+', 1, level) AS level1_flat from test connect by ... , select regexp_substr(val, '[^,]+', 1, 1) as val1, regexp_substr(val, '[^,]+', 1, 2) as ... value if there is a null element in the list and you want that item or one after it. ... create your own built-in cto_table function to split a str, Depends on the consistency of the data - assuming a single space is the separator between what you want to appear in column one vs two:, select regexp_substr(pq, '[^,]+', 1, 1) as po, regexp_substr(pq, '[^,]+', 1, 2) as qty from ( select regexp_substr('po1,qty1,po2,qty2','[^,]+,[^,]+', 1, ...,The select level from dual connect by level <= (...) uses a hierarchical query to create a column with an increasing number of matches found, from 1 to the total ... ,SELECT TRIM( SUBSTR( department_name, 1, INSTR( department_name, '[' ) - 1 ) ) AS department_name, SUBSTR( department_name, INSTR( ...
| 相關軟體 Oracle Database Express 資訊 | |
|---|---|
 oracle sql split string into columns 相關參考資料
divide the comma separated string into columns | Oracle ...
Splitting into rows or columns.... very commonly asked question on these forums... SQL> ed Wrote file afiedt.buf 1 with t as (select 'abcd,123 ... https://community.oracle.com How I can split string into columns and rows in Oracle? - Stack ...
Since it a single row, you need to first split the string into multiple rows using new line character as delimiter. And then, you could do it using simple SUBSTR and ... https://stackoverflow.com oracle split comma delimited string into columns - Stack ...
REGEXP_SUBSTR to the rescue! with sample_data as (select 'p1.pm.100' charge_num, '1.1.1,1000' mapping_col from dual union all select ... https://stackoverflow.com Parse string then flatten into columns - Ask Tom - Oracle
I want to split the strings into two columns so that the records are at 'Level2' ... select id, regexp_substr(string,'[^,]+', 1, level) AS level1_flat from test connect by ... https://asktom.oracle.com Parse string then flatten into columns - AskTom - Oracle
I want to split the strings into two columns so that the records are at 'Level2' ... select id, regexp_substr(string,'[^,]+', 1, level) AS level1_flat from test connect by ... https://asktom.oracle.com Split comma separated values to columns in Oracle - Stack ...
select regexp_substr(val, '[^,]+', 1, 1) as val1, regexp_substr(val, '[^,]+', 1, 2) as ... value if there is a null element in the list and you want that item or one after it. ... cre... https://stackoverflow.com Split varchar into separate columns in Oracle - Stack Overflow
Depends on the consistency of the data - assuming a single space is the separator between what you want to appear in column one vs two: https://stackoverflow.com Splitting Comma Separated string into columns by using ...
select regexp_substr(pq, '[^,]+', 1, 1) as po, regexp_substr(pq, '[^,]+', 1, 2) as qty from ( select regexp_substr('po1,qty1,po2,qty2','[^,]+,[^,]+', 1, ... https://dba.stackexchange.com Splitting string into multiple rows in Oracle - Stack Overflow
The select level from dual connect by level <= (...) uses a hierarchical query to create a column with an increasing number of matches found, from 1 to the total ... https://stackoverflow.com Splitting strings into 2 columns Oracle - Stack Overflow
SELECT TRIM( SUBSTR( department_name, 1, INSTR( department_name, '[' ) - 1 ) ) AS department_name, SUBSTR( department_name, INSTR( ... https://stackoverflow.com |