mysql in implode
Try this: select concat(last_name," ",first_name) as FullName from ( select SUBSTRING_INDEX(SUBSTRING_INDEX(name, ' ', 2), ' ', -1) AS ...,As mentioned in the comments, I would loop over your values and add a question mark for every value and then bind the values to these placeholders after you ... ,$ids = array(); while ($row = mysql_fetch_assoc($result)) $ids[] = $row["UserID"]; } echo implode(", ", $ids);. Replace "UserID" with the columnname of the id in ... ,HEY GUYS I implode a data from checkboxes this is the code: To Show Checkboxes from Different tables: <?php $query23 = "SELECT * from tbl_occasions"; ... ,As @Barmar has pointed out, the problem is your quotes are on the outside of your variable. I think this may be an easier to follow/cleaner way of fixing this ... ,The problem is the two ” in the beginning and the end of the IN block. They cause the entire implode array to become a comma-separated string. , Later on, you query using those values imploded together: $keywords_imploded = implode("','",$keywords); $myquery = sql_query("SELECT ...,$query = 'SELECT name FROM user WHERE city IN ('.implode(',',$cities).')'; $result = $db->fetchAll( $query ); }. This works out fine until someone passes $cities ... ,Note: The implode() function accept its parameters in either order. However, for consistency with explode(), you should use the documented order of arguments. , the naive solution will be: $array = ['Cat1', 'Cat2', 'Cat3']; echo "'" . implode("','", $array) . "'";. but it could introduce sql injection, so you need ...
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mysql in implode 相關參考資料
Explode and implode strings in mysql query - Stack Overflow
Try this: select concat(last_name," ",first_name) as FullName from ( select SUBSTRING_INDEX(SUBSTRING_INDEX(name, ' ', 2), ' ', -1) AS ... https://stackoverflow.com ExplodeImplode List for Mysql WHERE IN () - Stack Overflow
As mentioned in the comments, I would loop over your values and add a question mark for every value and then bind the values to these placeholders after you ... https://stackoverflow.com implode an array into a comma separated string from mysql query ...
$ids = array(); while ($row = mysql_fetch_assoc($result)) $ids[] = $row["UserID"]; } echo implode(", ", $ids);. Replace "UserID" with the columnname of the id in ..... https://stackoverflow.com Implode and explode php mysql - Stack Overflow
HEY GUYS I implode a data from checkboxes this is the code: To Show Checkboxes from Different tables: <?php $query23 = "SELECT * from tbl_occasions"; ... https://stackoverflow.com implode() array to insert record into mySql database - Stack Overflow
As @Barmar has pointed out, the problem is your quotes are on the outside of your variable. I think this may be an easier to follow/cleaner way of fixing this ... https://stackoverflow.com Imploded PHP integer array for Mysql NOT IN clause - Stack Overflow
The problem is the two ” in the beginning and the end of the IN block. They cause the entire implode array to become a comma-separated string. https://stackoverflow.com Imploding an array into a MySQL query - Stack Overflow
Later on, you query using those values imploded together: $keywords_imploded = implode("','",$keywords); $myquery = sql_query("SELECT ... https://stackoverflow.com PHP implode array to generate mysql IN criteria - Stack Overflow
$query = 'SELECT name FROM user WHERE city IN ('.implode(',',$cities).')'; $result = $db->fetchAll( $query ); }. This works out fine until someone passes $cities ... https://stackoverflow.com PHP implode() Function - W3Schools
Note: The implode() function accept its parameters in either order. However, for consistency with explode(), you should use the documented order of arguments. https://www.w3schools.com using implode for array inside mysql where in clause - Stack Overflow
the naive solution will be: $array = ['Cat1', 'Cat2', 'Cat3']; echo "'" . implode("','", $array) . "'";. but it could introduce s... https://stackoverflow.com |