list index out of range python for loop
You shouldn't remove items from the list as you iterate over it; that changes the indices of all subsequent items, hence the IndexError . You could try a simple list ... ,An list with n elements has items in indexes 0 through n-1 . I.e., your loop should stop before n , not at it. Replace <= with < and you should be OK: while item < n: ... , If I understand you correctly, you're trying to sort a list of numbers. There's a built-in Python method for this, that has been optimized for ages to ..., You're out of range, because j is taking the values of the elements of the N array, not the index. So, j is not 0, 1, 2, 3 but rather 20, 40, 60, 80., You have some strange indenting and without the contents I'm not sure where your error would be, but this should help you find it:,You probably meant to do: for j in range(len(res)): for k in range(2,res[j]):. Using for j in res will iterate over res elements. ,, Try this i =0 for i in xrange(0,len(doc) -1) date = doc[i] sentence = doc[i + 1] sentiment = classifier.classify(word_feats_test(sentence)) ..., Let's reduce this to a MCVE: signature = [1, 1, 1] count = 0 while True: newitem = signature[count] + signature[count+1] + signature[count+2] ...,off by 1 error. arrays are zero-based in Python and therefore start at index 0. You're starting at array[1] in your loop, when you should be starting ...
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 list index out of range python for loop 相關參考資料
(Python) List index out of range - iteration - Stack Overflow
You shouldn't remove items from the list as you iterate over it; that changes the indices of all subsequent items, hence the IndexError . You could try a simple list ... https://stackoverflow.com IndexError: list index out of range in while loop - Stack Overflow
An list with n elements has items in indexes 0 through n-1 . I.e., your loop should stop before n , not at it. Replace <= with < and you should be OK: while item < n: ... https://stackoverflow.com IndexError: list index out of range with a while loop - Stack Overflow
If I understand you correctly, you're trying to sort a list of numbers. There's a built-in Python method for this, that has been optimized for ages to ... https://stackoverflow.com List index out of range error on simple python for loop - Stack ...
You're out of range, because j is taking the values of the elements of the N array, not the index. So, j is not 0, 1, 2, 3 but rather 20, 40, 60, 80. https://stackoverflow.com List index out of range python in a for loop - Stack Overflow
You have some strange indenting and without the contents I'm not sure where your error would be, but this should help you find it: https://stackoverflow.com Python for loop: "list index out of range" error? - Stack Overflow
You probably meant to do: for j in range(len(res)): for k in range(2,res[j]):. Using for j in res will iterate over res elements. https://stackoverflow.com Python Loop: List Index Out of Range - Stack Overflow
https://stackoverflow.com Python: list index out of range - whilefor loop - Stack Overflow
Try this i =0 for i in xrange(0,len(doc) -1) date = doc[i] sentence = doc[i + 1] sentiment = classifier.classify(word_feats_test(sentence)) ... https://stackoverflow.com Python: List index out of range inside whilefor loop - Stack Overflow
Let's reduce this to a MCVE: signature = [1, 1, 1] count = 0 while True: newitem = signature[count] + signature[count+1] + signature[count+2] ... https://stackoverflow.com [Python 3] List index out of range error in a for loop ...
off by 1 error. arrays are zero-based in Python and therefore start at index 0. You're starting at array[1] in your loop, when you should be starting ... https://www.reddit.com |