if no direction is specified key_or_list must be a
sort should be a list of key-direction pairs, that is db.test.find("number": "$gt": 1}}).sort([("number", 1), ("date", -1)]). The reason why this has to be a list is that the ... ,2019年9月4日 — collection.find().sort("_id":-1) should do it - without the '}'. you can also try : collection.find().sort("_id": pymongo.ASCENDING) when using ... ,2019年6月9日 — I have a TypeError: if no direction is specified, key_or_list must be an instance of list . I have created the method create_index , and I want this ... ,2020年4月18日 — ... TypeError: if no direction is specified, key_or_list must be an instance of list. what is wrong here ?? @app.route('/connect', methods=['GET', ... ,Your syntax doesn't really seem quite right there. db.collection.find(}).sort("_id", -1).limit(N). Should do what you would expect. Python and pymongo support ... ,2017年12月19日 — TypeError: if no direction is specified, key_or_list must be an instance of list ... sort(key_or_list, direction=None). Sorts this cursor's results. Pass a field name and a direction, either ASCENDING or DESCENDING [docs]. ,2016年2月25日 — 使用pymongo对某一字段进行sort时，报错 TypeError: if no direction is specified, key_or_list must be an instance of list问题代码：items = db. ,2020年5月2日 — 解决方法： db.collection.find().sort([("name", 1), ("age" , 1)]) 原因：在python中只能使用列表进行排.
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 if no direction is specified key_or_list must be a 相關參考資料
Using .sort with PyMongo - Stack Overflow
sort should be a list of key-direction pairs, that is db.test.find("number": "$gt": 1}}).sort([("number", 1), ("date", -1)]). The reason why this has to be a li... https://stackoverflow.com TypeError: if no direction is specified, key_or_list must be an ...
2019年9月4日 — collection.find().sort("_id":-1) should do it - without the '}'. you can also try : collection.find().sort("_id": pymongo.ASCENDING) when using ... https://stackoverflow.com How to fix "TypeError: if no direction is specified, key_or_list ...
2019年6月9日 — I have a TypeError: if no direction is specified, key_or_list must be an instance of list . I have created the method create_index , and I want this ... https://stackoverflow.com Getting TypeError: if no direction is specified, key_or_list must ...
2020年4月18日 — ... TypeError: if no direction is specified, key_or_list must be an instance of list. what is wrong here ?? @app.route('/connect', methods=['GET', ... https://stackoverflow.com pymongo - querying most recent N items - Stack Overflow
Your syntax doesn't really seem quite right there. db.collection.find(}).sort("_id", -1).limit(N). Should do what you would expect. Python and pymongo support ... https://stackoverflow.com Pymongo LastRecord Sort Error - Stack Overflow
2017年12月19日 — TypeError: if no direction is specified, key_or_list must be an instance of list ... sort(key_or_list, direction=None). Sorts this cursor's results. Pass a field name and a directio... https://stackoverflow.com Pymongo: TypeError: if no direction is specified, key_or_list ...
2016年2月25日 — 使用pymongo对某一字段进行sort时，报错 TypeError: if no direction is specified, key_or_list must be an instance of list问题代码：items = db. https://blog.csdn.net mongodb 排序输出if no direction is specified, key_or_list must ...
2020年5月2日 — 解决方法： db.collection.find().sort([("name", 1), ("age" , 1)]) 原因：在python中只能使用列表进行排. https://www.cnblogs.com |