hex to string c
0xaa overflows when plain char is signed, use unsigned char : #include <stdio.h> int main(void) unsigned char readingreg[4]; readingreg[0] = 0x4a; readingreg[1] = 0xaa; readingreg[2] = 0xaa; readingreg[3] = 0xa0; char temp[4]; sprintf(temp, ",Perhaps you need: &hex_tmp[i * 2]. And also a bigger array. , You cannot simply 'cast', you will need to use sprintf to do the convertion: unsigned int hex = 0xABC123FF; char hexString[256]; sprintf(hexString, "0x%08X", hex);. If you want to 'cast' it to string in order to print it, you ca, you need to take 2 (hex) chars at the same time... then calculate the int value and after that make the char conversion like... char d = (char)intValue;. do this for every 2chars in the hex string. this works if the string chars are only 0-9A-F: #include, Your code has several problems. First unsigned char temp[10]; should be unsigned char temp[11]; to contain a string terminator. Next is the format spec "%x" should be "%02x" so each value is 2 digits. Then temp + i should be temp + i*, Change your "s" variable line from. int s = atoi(substr);. to. int s = strtol(substr, NULL, 16);.,/* allocate the buffer */ char * buffer = malloc((strlen(s) / 2) + 1); char *h = s; /* this will walk through the hex string */ char *b = buffer; /* point inside the buffer */ /* offset into this string is the numeric value */ char xlate[] = "0123456, int main() char arr[4]; arr[0] = 0x11; arr[1] = 0xc0; arr[2] = 0x0c; arr[3] = 0x00; size_t len = sizeof(arr) / sizeof(*arr); char* str = (char*)malloc(len * 2 + 1); for (size_t i = 0; i < len; i++) const static char table[] = '0', '1,printf("%02X:%02X:%02X:%02X", buf[0], buf[1], buf[2], buf[3]);. for a more generic way: int i; for (i = 0; i < x; i++) if (i > 0) printf(":"); printf("%02X", buf[i]); } printf("-n");. to concatenate to a stri, No "oneliner", no. Besides, your code looks broken. You can't use sizeof like that, you probably mean strlen() . And you need to cast the character to an unsigned type to be safe. So, something like this, perhaps: void print_hex(const char
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 hex to string c 相關參考資料
arrays - Converting hex to string in C? - Stack Overflow
0xaa overflows when plain char is signed, use unsigned char : #include <stdio.h> int main(void) unsigned char readingreg[4]; readingreg[0] = 0x4a; readingreg[1] = 0xaa; readingreg[2] = 0xaa; r... https://stackoverflow.com c - Converting hex into a string using 'sprintf' - Stack Overflow
Perhaps you need: &hex_tmp[i * 2]. And also a bigger array. https://stackoverflow.com casting - How to cast from hexadecimal to string in C? - Stack ...
You cannot simply 'cast', you will need to use sprintf to do the convertion: unsigned int hex = 0xABC123FF; char hexString[256]; sprintf(hexString, "0x%08X", hex);. If you want to &... https://stackoverflow.com c - Hex to ascii string conversion - Stack Overflow
you need to take 2 (hex) chars at the same time... then calculate the int value and after that make the char conversion like... char d = (char)intValue;. do this for every 2chars in the hex string. t... https://stackoverflow.com arrays - C - converting hex to string - Stack Overflow
Your code has several problems. First unsigned char temp[10]; should be unsigned char temp[11]; to contain a string terminator. Next is the format spec "%x" should be "%02x" so ea... https://stackoverflow.com Convert to ASCII String from hex String in C - Stack Overflow
Change your "s" variable line from. int s = atoi(substr);. to. int s = strtol(substr, NULL, 16);. https://stackoverflow.com c - Convert hex string to string of bytes - Stack Overflow
/* allocate the buffer */ char * buffer = malloc((strlen(s) / 2) + 1); char *h = s; /* this will walk through the hex string */ char *b = buffer; /* point inside the buffer */ /* offset into this stri... https://stackoverflow.com C hex character array to string representation - Stack Overflow
int main() char arr[4]; arr[0] = 0x11; arr[1] = 0xc0; arr[2] = 0x0c; arr[3] = 0x00; size_t len = sizeof(arr) / sizeof(*arr); char* str = (char*)malloc(len * 2 + 1); for (size_t i = 0; i < len; i+... https://stackoverflow.com How do you convert a byte array to a hexadecimal string in C ...
printf("%02X:%02X:%02X:%02X", buf[0], buf[1], buf[2], buf[3]);. for a more generic way: int i; for (i = 0; i < x; i++) if (i > 0) printf(":"); printf("%02X", buf[i... https://stackoverflow.com c - Oneliner for printing string in hex? - Stack Overflow
No "oneliner", no. Besides, your code looks broken. You can't use sizeof like that, you probably mean strlen() . And you need to cast the character to an unsigned type to be safe. So, s... https://stackoverflow.com |