for loop in unix using variable
Either use another shell like zsh or ksh93 or use an alternative syntax: ... Using loops in a shell script are often an indication that you're not doing it right. , But you probably would prefer to use arrays rather than dynamic variable names as this can be seen as a bad practice and make your code ...,Now as an answer to the question in the title, for a shell with for loops taking more than one variables, you've got zsh (you seem to already be using zsh syntax ... , One way is using eval : for i in $( eval echo 0..$length} ) do echo "do something right $i" done. Note what happens when you set length=;ls or ..., To fix this problem use three-expression bash for loops syntax which share a common heritage with the C programming language. It is characterized by a three-parameter loop control expression; consisting of an initializer (EXP1), a loop-test or condition ,In bash, is it possible to use an integer variable in the loop control of a for loop? The first for loop (without the variable upperlim in the loop control) works fine, but the second for loop (with the variable upperlim in the loop control) does not. , Use an array. #! /bin/bash servers=( 192.xxx.xxx.2 192.xxx.xxx.3 192.xxx.xxx.4 192.xxx.xxx.5 192.xxx.xxx.6 192.xxx.xxx.7 ) for server in ..., The exit status of a for loop compound command is that of the last command executed in it¹. for cmd in true false; do "$cmd" done. Returns false ...,You need to use a nested for loop for i in `cat days` do for j in `cat hours` do cat file | grep "$i $j" >data-$i}-$j} done done.
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 for loop in unix using variable 相關參考資料
bash variables in for loop range - Unix & Linux Stack Exchange
Either use another shell like zsh or ksh93 or use an alternative syntax: ... Using loops in a shell script are often an indication that you're not doing it right. https://unix.stackexchange.com echo variable name in for loop - Unix & Linux Stack Exchange
But you probably would prefer to use arrays rather than dynamic variable names as this can be seen as a bad practice and make your code ... https://unix.stackexchange.com how can we use multiple variables in single for loop in shell ...
Now as an answer to the question in the title, for a shell with for loops taking more than one variables, you've got zsh (you seem to already be using zsh syntax ... https://unix.stackexchange.com How to use variables in a bash for loop - Stack Overflow
One way is using eval : for i in $( eval echo 0..$length} ) do echo "do something right $i" done. Note what happens when you set length=;ls or ... https://stackoverflow.com HowTo: Iterate Bash For Loop Variable Range Under Unix ...
To fix this problem use three-expression bash for loops syntax which share a common heritage with the C programming language. It is characterized by a three-parameter loop control expression; consist... https://www.cyberciti.biz In bash, is it possible to use an integer variable in the loop ...
In bash, is it possible to use an integer variable in the loop control of a for loop? The first for loop (without the variable upperlim in the loop control) works fine, but the second for loop (with t... https://unix.stackexchange.com Loop Through Variables - Unix & Linux Stack Exchange
Use an array. #! /bin/bash servers=( 192.xxx.xxx.2 192.xxx.xxx.3 192.xxx.xxx.4 192.xxx.xxx.5 192.xxx.xxx.6 192.xxx.xxx.7 ) for server in ... https://unix.stackexchange.com Print variable inside loop - Unix & Linux Stack Exchange
The exit status of a for loop compound command is that of the last command executed in it¹. for cmd in true false; do "$cmd" done. Returns false ... https://unix.stackexchange.com Shell: how to use 2 variables with for condition - Unix & Linux ...
You need to use a nested for loop for i in `cat days` do for j in `cat hours` do cat file | grep "$i $j" >data-$i}-$j} done done. https://unix.stackexchange.com |