bool array to int
So I'm taking user input from a four dip-switches and storing the bit values in a bool array, and then converting that to int/hex. now here is the issue: It works fine till 0011 which it shows as 3, But it also shows 0100 as 3 which should be 4. And f, This will do what you want: sum(v<<i for i, v in enumerate(p[::-1]))., O(n): int bitArrayToInt32(bool arr[], int count) int ret = 0; int tmp; for (int i = 0; i < count; i++) tmp = arr[i]; ret |= tmp << (count - i - 1); } return ret; } ..., Yes, you can use the BitArray class. Something like this should do it: BitArray arr = new BitArray(BoolArray); byte[] data = new byte[1]; arr., These two arrays array<array<bool,19>,19> tablero. and array<array<int,19>,19> lab;. have different types and there is no implicit conversion ..., Numpy arrays have an astype method. Just do y.astype(int) . Note that it might not even be necessary to do this, depending on what you're ..., Ok, the easiest way to change a type of any array to float is doing: data.astype(float). The issue with your array is that float('True') is an error, ...,Ok, the easiest way to change a type of any array to float is doing: data.astype(float). The issue with your array is that float('True') is an error, because 'True' can't ... , This will work: int n = (a[0] ? 2 : 0) + (a[1] ? 1 : 0);. If you want a more general solution: int n = 0, l = a.length; for (int i = 0; i < l; ++i) n = (n << 1) + ..., Why go via a byte? You can go straight to uint. Unfortunately C#/.Net doesn't have bit booleans so I am not aware of a better approach than.
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 bool array to int 相關參考資料
bool array binary to int conversion [Solved #7 and #9] - Arduino Forum
So I'm taking user input from a four dip-switches and storing the bit values in a bool array, and then converting that to int/hex. now here is the issue: It works fine till 0011 which it shows as ... https://forum.arduino.cc Bool array to integer - Stack Overflow
This will do what you want: sum(v<<i for i, v in enumerate(p[::-1])). https://stackoverflow.com Convert bool array to int32 ,unsigned int and double? - Stack Overflow
O(n): int bitArrayToInt32(bool arr[], int count) int ret = 0; int tmp; for (int i = 0; i < count; i++) tmp = arr[i]; ret |= tmp << (count - i - 1); } return ret; } ... https://stackoverflow.com Converting a boolean array into a hexadecimal number - Stack Overflow
Yes, you can use the BitArray class. Something like this should do it: BitArray arr = new BitArray(BoolArray); byte[] data = new byte[1]; arr. https://stackoverflow.com Converting array of bool to array of int - Stack Overflow
These two arrays array<array<bool,19>,19> tablero. and array<array<int,19>,19> lab;. have different types and there is no implicit conversion ... https://stackoverflow.com How to convert a boolean array to an int array - Stack Overflow
Numpy arrays have an astype method. Just do y.astype(int) . Note that it might not even be necessary to do this, depending on what you're ... https://stackoverflow.com How to convert from boolean array to int array in python - Stack ...
Ok, the easiest way to change a type of any array to float is doing: data.astype(float). The issue with your array is that float('True') is an error, ... https://stackoverflow.com How to convert from boolean array to int array in python ...
Ok, the easiest way to change a type of any array to float is doing: data.astype(float). The issue with your array is that float('True') is an error, because 'True' can't ... https://stackoverflow.com Java: Convert bool array into a single int - Stack Overflow
This will work: int n = (a[0] ? 2 : 0) + (a[1] ? 1 : 0);. If you want a more general solution: int n = 0, l = a.length; for (int i = 0; i < l; ++i) n = (n << 1) + ... https://stackoverflow.com [Solved] How to convert a bool array to a byte, and further to an ...
Why go via a byte? You can go straight to uint. Unfortunately C#/.Net doesn't have bit booleans so I am not aware of a better approach than. https://www.codeproject.com |