bash for loop variable
If the first character of parameter is an exclamation point (!), a level of variable indirection is introduced. Bash uses the value of the variable formed from the rest ... , Yes, that's because brace-expansion occurs before parameter expansion. Either use another shell like zsh or ksh93 or use an alternative ...,You should specify the increment with seq: seq $FROMHERE -1 1. ,Pax Diablo suggested a Bash loop to avoid calling a subprocess, with the additional .... If the shell variable x contains a value that forms a valid integer constant, ... , One way is using eval : for i in $( eval echo 0..$length} ) do echo "do something right $i" done. Note what happens when you set length=;ls or ..., How can I iterate bash for loop using a variable range of numbers in Unix or Linux or BSD or Apple OS X operating systems? You can use the ...,This way, you avoid the common problem of I set variables in a loop that's in a pipeline. ... There is no need to use cut , you can stick with pure bash solutions. ,#!/bin/bash ## declare an array variable declare -a array=("one" "two" "three") # get length of an array arraylength=$#array[@]} # use for loop to read all values ... , It's really easy, you can just redirect the output of the whole loop to a variable (if you want to use just one variable as stated): VARIABLE=$(for ..., You can use for loop like this to iterate with a variable $TOP : for ((i=1; i<=$TOP; i++)) do echo $i # rest of your code done.
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 bash for loop variable 相關參考資料
Bash for loop on variable numbers - Stack Overflow
If the first character of parameter is an exclamation point (!), a level of variable indirection is introduced. Bash uses the value of the variable formed from the rest ... https://stackoverflow.com bash variables in for loop range - Unix & Linux Stack Exchange
Yes, that's because brace-expansion occurs before parameter expansion. Either use another shell like zsh or ksh93 or use an alternative ... https://unix.stackexchange.com descending loop with variable bash - Stack Overflow
You should specify the increment with seq: seq $FROMHERE -1 1. https://stackoverflow.com How do I iterate over a range of numbers defined by variables in ...
Pax Diablo suggested a Bash loop to avoid calling a subprocess, with the additional .... If the shell variable x contains a value that forms a valid integer constant, ... https://stackoverflow.com How to use variables in a bash for loop - Stack Overflow
One way is using eval : for i in $( eval echo 0..$length} ) do echo "do something right $i" done. Note what happens when you set length=;ls or ... https://stackoverflow.com HowTo: Iterate Bash For Loop Variable Range Under Unix Linux ...
How can I iterate bash for loop using a variable range of numbers in Unix or Linux or BSD or Apple OS X operating systems? You can use the ... https://www.cyberciti.biz Incrementing a variable inside a Bash loop - Stack Overflow
This way, you avoid the common problem of I set variables in a loop that's in a pipeline. ... There is no need to use cut , you can stick with pure bash solutions. https://stackoverflow.com Loop through an array of strings in Bash? - Stack Overflow
#!/bin/bash ## declare an array variable declare -a array=("one" "two" "three") # get length of an array arraylength=$#array[@]} # use for loop to read all values ..... https://stackoverflow.com Store for loop results as a variable in bash - Stack Overflow
It's really easy, you can just redirect the output of the whole loop to a variable (if you want to use just one variable as stated): VARIABLE=$(for ... https://stackoverflow.com Writing a bash for-loop with a variable top-end - Stack Overflow
You can use for loop like this to iterate with a variable $TOP : for ((i=1; i<=$TOP; i++)) do echo $i # rest of your code done. https://stackoverflow.com |