ajax get tag name
Is this what you're looking for? function swap(element) var name = element.attributes.getNamedItem("name").value; var nameValue = name.split('-')[1]; // do ... ,If I assigned it directly to the element via its id, it does work $('#1').attr('title', .... the data parameter, does not get executed until after the ajax call is complete. , If the HTML is more complex than a single tag without attributes, as it ... During this process, some browsers filter out certain elements such as < html >, < title > ... get a page using AJAX $.get('/',function(d) // create a tempora,I am new to jQuery, but I will give it a try anyways: var newTitle = $(responseHtml).filter('title').text();. And if one of the above works, the current title could be ... ,filter() returns a jQuery object, not a DOM element, so you have to use the val() ... your setup and found two problems you need tor resolve to get this to work. ,Are you getting anything back in those other browsers? Maybe the xml is coming back with the wrong mime type? Your probably better off using the selector ... ,<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"> .... You can get the name value from an input field using name element in jQuery by:. ,$(function() var htmlStr='<html><head><title>My Title X</title></head><body><div class="NewDiv">Data in the DIV in html string</div></body></html>'; ... , "body" tag filtering by jQuery when getting from string. So $(data)[0] will back all content, without body. Also use filter, not "find" So you can get ..., Select an element that has a class name of “classTag1”, and use the .get(0).tagName function to display its tag name. $('.classTag1').get(0).
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 ajax get tag name 相關參考資料
ajax get anchor tag name - Stack Overflow
Is this what you're looking for? function swap(element) var name = element.attributes.getNamedItem("name").value; var nameValue = name.split('-')[1]; // do ... https://stackoverflow.com change title attribute via jQuery ajax.get call - Stack Overflow
If I assigned it directly to the element via its id, it does work $('#1').attr('title', .... the data parameter, does not get executed until after the ajax call is complete. https://stackoverflow.com Find body tag in an ajax HTML response - Stack Overflow
If the HTML is more complex than a single tag without attributes, as it ... During this process, some browsers filter out certain elements such as < html >, < title > ... get a page using... https://stackoverflow.com Get the title of a requested page using jQuery AJAX - Stack Overflow
I am new to jQuery, but I will give it a try anyways: var newTitle = $(responseHtml).filter('title').text();. And if one of the above works, the current title could be ... https://stackoverflow.com getelementsbyname (in an Ajax html response) when I have a partial ...
filter() returns a jQuery object, not a DOM element, so you have to use the val() ... your setup and found two problems you need tor resolve to get this to work. https://stackoverflow.com Getting XML Element by name in ajax responseXML? - Stack Overflow
Are you getting anything back in those other browsers? Maybe the xml is coming back with the wrong mime type? Your probably better off using the selector ... https://stackoverflow.com How can I select an element by name with jQuery? - Stack Overflow
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"> .... You can get the name value from an input field using name element in jQuery by:. https://stackoverflow.com How to get any element from an ajax responsetext (or any html text ...
$(function() var htmlStr='<html><head><title>My Title X</title></head><body><div class="NewDiv">Data in the DIV in html string</div></b... https://stackoverflow.com jQuery - How to get an element's class from ajax request - Stack ...
"body" tag filtering by jQuery when getting from string. So $(data)[0] will back all content, without body. Also use filter, not "find" So you can get ... https://stackoverflow.com jQuery – How to get the tag name – Mkyong.com
Select an element that has a class name of “classTag1”, and use the .get(0).tagName function to display its tag name. $('.classTag1').get(0). https://www.mkyong.com |