std function member function
print_num is a non-static member function, which means that it has an implicit first argument of type A* . You can, for instance, pass that by using a lambda: ,FWIW, this is not just std::function, but any std algorithm too -- function pointers are slow because they can't (generally) be inlined. For example: bool compare(int a, ... , std::function is perfectly capable of storing a member function pointer directly. However, you have to adjust the argument list appropriately., print_add is a non-static member function of foo , which means it must be invoked on an instance of Foo ; hence it has an implicit first argument, ...,跳到 Member functions - (Args)==2 and T2 is the second of the two types in Args... [edit] Member functions. (constructor). constructs ... , Funcp func = std::bind(&A::func, &a, std::placeholders::_1, std::placeholders::_2);.,What will happen is undefined behavior. The bind() call will return some object that contains a copy of instance , so that when you call func(0) will effectively call: ,A non-static member function must be called with an object. That is, it always implicitly passes "this" pointer as its argument. Because your std::function signature ...
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 std function member function 相關參考資料
assigning std::function to a member function - Stack Overflow
print_num is a non-static member function, which means that it has an implicit first argument of type A* . You can, for instance, pass that by using a lambda: https://stackoverflow.com Binding std::function to member functions : cpp - Reddit
FWIW, this is not just std::function, but any std algorithm too -- function pointers are slow because they can't (generally) be inlined. For example: bool compare(int a, ... https://www.reddit.com How do i write a pointer-to-member-function with std::function ...
std::function is perfectly capable of storing a member function pointer directly. However, you have to adjust the argument list appropriately. https://stackoverflow.com How to initialize `std::function` with a member-function ...
print_add is a non-static member function of foo , which means it must be invoked on an instance of Foo ; hence it has an implicit first argument, ... https://stackoverflow.com std::function - cppreference.com
跳到 Member functions - (Args)==2 and T2 is the second of the two types in Args... [edit] Member functions. (constructor). constructs ... https://en.cppreference.com std::function to member function - Stack Overflow
Funcp func = std::bind(&A::func, &a, std::placeholders::_1, std::placeholders::_2);. https://stackoverflow.com std::function to member function of object and lifetime of object ...
What will happen is undefined behavior. The bind() call will return some object that contains a copy of instance , so that when you call func(0) will effectively call: https://stackoverflow.com Using generic std::function objects with member functions in ...
A non-static member function must be called with an object. That is, it always implicitly passes "this" pointer as its argument. Because your std::function signature ... https://stackoverflow.com |