javascript switch case always
I don't want to lean too far out of the window, but I would almost guarantee you that the return value from your ajax request does not fit 100% your case 'es. ,The switch statement evaluates an expression. The value of the expression is then compared with the values of each case in the structure. If there is a match, the associated block of code is executed. The switch statement is often used together with a bre, dealerCards=[name:'ace'},name:'two'}] playerCards=[name:'three'},name:'three'}] updateCount(); //Update the count function ..., up vote 3 down vote. Javascript's case tests are strict: if discselect is a string and not a number, your code will always take the default branch., switch 語句會比對一個表達式 裡頭的值是否符合 case 條件,然後執行跟這個條件相關的 陳述式, 以及此一符合條件以外,剩下其他條件裡的陳述 ..., function CheckNums(num1, num2) switch (Math.sign(num1 - num2)) case -1: console.log('num2 greater than num1'); break; case 0: ..., Which means unless stueckzahl is true/false , it will always go to default ... Switch expression is compared to the the different case values., Hard to explain why, but the default: case also need a break; statement after it like all the other cases. When calling the switch-version with a plain 2 , it works as expected. Calling it with '2' makes it drop through to the default line. The i, ... with break at the beginning of a switch statement, why wouldn't the default always ... The default keyword specifies the code to run if there is no case match ... Semantics: CaseBlockEvaluation (that's the definition of JavaScript). ... to th
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javascript switch case always 相關參考資料
Javascript switch always default - Stack Overflow
I don't want to lean too far out of the window, but I would almost guarantee you that the return value from your ajax request does not fit 100% your case 'es. https://stackoverflow.com JavaScript switch Statement - W3Schools
The switch statement evaluates an expression. The value of the expression is then compared with the values of each case in the structure. If there is a match, the associated block of code is executed.... https://www.w3schools.com JavaScript: My switch statement always defaults to the first case ...
dealerCards=[name:'ace'},name:'two'}] playerCards=[name:'three'},name:'three'}] updateCount(); //Update the count function ... https://stackoverflow.com JS Switch case not working correctly always default is executed ...
up vote 3 down vote. Javascript's case tests are strict: if discselect is a string and not a number, your code will always take the default branch. https://stackoverflow.com switch - JavaScript | MDN - Mozilla
switch 語句會比對一個表達式 裡頭的值是否符合 case 條件,然後執行跟這個條件相關的 陳述式, 以及此一符合條件以外,剩下其他條件裡的陳述 ... https://developer.mozilla.org switch statement always goes to default in javascript - Stack Overflow
function CheckNums(num1, num2) switch (Math.sign(num1 - num2)) case -1: console.log('num2 greater than num1'); break; case 0: ... https://stackoverflow.com switchcase always returns default value - Stack Overflow
Which means unless stueckzahl is true/false , it will always go to default ... Switch expression is compared to the the different case values. https://stackoverflow.com trouble with SWITCH javascript always executing default case ...
Hard to explain why, but the default: case also need a break; statement after it like all the other cases. When calling the switch-version with a plain 2 , it works as expected. Calling it with '... https://stackoverflow.com Using break after default in switch statement when default not at ...
... with break at the beginning of a switch statement, why wouldn't the default always ... The default keyword specifies the code to run if there is no case match ... Semantics: CaseBlockEvaluati... https://stackoverflow.com |